Write a program that asks the user for a date in the format mm/dd/, using a custom struct to store the date information entered in memory. the program should call a custom function that adds seven days to the user's date, passing in the data in and out of the custom function using the custom struct for the dates. the program should then print out the original date entered and the date one week late. anyway, here is the code, check: #include struct date//structure declaration{int day, month, year; //date, month, year; }; void addseven(struct date d)//function which adds 7 to present date and prints to stdout{int m[] ={31,28,31,30,31,30,31,31,30,31,30, 31}; //array to keep track of days in monthd. day = d. day+7; //incrementing daysif(d. day> m[d. month-1])//if exceeds monthly days limit then{int k=d. day-m[d. month-1]; d. day = k; d. month = d. month+1; //increment month countif(d. month> 12)//if month exceeded 12{d. year =d. year+1; //incrementing yeard. month=1; }}//printing resultprintf("date after one week : %d/%d/%d\n",d. month, d.day, d.year); }int main(){struct date present; //present datechar c[10]; printf("enter date in format(mm/dd/) : "); scanf("%s",c); //reading as stringint i=0,k=0,l, s=0; for(i=0; c[i]! ='\0'; i++)//converting to and storing in structure{if(c[i]=='/' & & k==0){k=1; present. month = s; //storing months=0; }else if (c[i]=='/' & & k==1){k=2; present. day = s; //storing days=0; }else {l = (int)c[i]-48; s =s*10+l; }}present. year =s; //storing year//printing present dateprintf("present date : %d/%d/%d\n",present. month, present. day, present. year); addseven(present); //function callingreturn 0; }