You are given an array x of string elements along with an int variable n that contains the number of elements in the array. you are also given a string variable mode that has been declared. assign to mode the mode value of the array. (assume there are no "ties".)

Answer and Explanation:

Make an algorithm of that which include array x of string where Mode of the value of the array means that you have the values such that 1.2,4,2,6,7,8,2 so 2 is the value of set as it appears more than other number similarly when a array of x has been given.First of all initialize a variable then declare it . so for initialization create a variable .Let suppose i create a variable of add and initialize it with 0 and given a it data type integer then

int add= 0;  // declaration

int add[]=0; // declaration and initialization in array

class add {  

void main(String array[]){  

int add[]=0;//declaration and instantiation  

int add[] = new int [3];

add[0]=30;//initialization  

add[1]=80;  

add[2]=20;  

output the given array of string

for ( int i = 0 ; i <add.length ;i++)

cout <<add[i];

 }

Taking an other example let initialization and declare array of string and print the greater value.For this create a variable with integer data type \

class Test{  

void main(String[] array){  

       //declaration of array

int test[][] = new int [2];

test[0]; new int [2];

test[1]; new int [4];

for initialization of array lets take variable a with data type integer

      int a=0;  

//taking loop for condition

       for (int i=0; i<test.length; i++)  

           for(int j=0; j<test[i].length; j++)  

//if the loops working properly then take increment in the variable a

               test[i][j] = a++;  

this process repeat until loops got false

   for (int i=0; i<test.length; i++)  

           for(int j=0; j<test[i].length; j++)  

         cout<<test[i][j]<<"+"<<"";  

           }  

           System.out.println();

       }  

   }  

he could use bold or bigger text just a suggestion.