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True or false? aₙ₊₁ = 2aₙ₋₁ is a one-step recurrence relation. true or false? the recurrence relationaₙ = 4aₙ₋₁ + 5aₙ₋₂ for all n ≥ 2has exactly one solution (one and only one) for each ordered pair (a₀, a₁) of initial conditions .in other words, if s is the set of all sequences that satisfy the recurrence, the functionf: ℝ × ℝ → s; f(a, b) = the sequence {aₙ} ∈ s with a₀=a, a₁=bis well-defined, and a bijection.

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