(a) if the following switch statement were implemented using a jump table, how many elements would the table contain?

would it make sense to use a jump table to implement this switch statement? why or why not? if not then what type of implementation will be more suitable?

why?

switch (i) {

case 40: j = a; break;

case 41: j = b; break;

case 42: j = c; break;

case 43: j = d; break;

case 44: j = e; break;

case 45: j = r; break;

case 46: j = g; break;

}

(b) answer the same questions as in part (a), using the following switch statement instead:

switch (i) {

case 20: j = a; break;

case 67: j = b; break;

case 97: j = c; break;

case 400: j = d; break;

case 310: j = e; break;

case 10: j = f; break;

}

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }

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