2. trace through the following loop and show the values for a, b & c.
declare integer a
declare integer b
declare integer
assign a = 4
assign b = 3
assign c = 0
do while c assign b = b +c
assign c = c +1
end while
do until b = a
assign c = c-1
assign b = b-c
end until
noor more
o-rmt mń - -

At the beginning, we have

A = 4, B = 3, C = 0

Although you didn't specify the programming language, usually 0 means false, so we never enter the first loop, because "while C" is never true.

We enter the second loop because B is different from A, so we decrease C by 1, and we have

A = 4, B = 3, C = -1

and we assign B = B-C, so now B becomes 3-(-1)=3+1=4. Now B=A and we exit the second loop, and we have

A = 4, B = 4, C = -1