Write a function that takes in a string as input and returns a list of the unique characters used in the string. punctuation should not be counted as a unique character. for our purposes you may consider the following characters as punctuation: .,; : ? ! "'- your list should return all letters as lower case and sorted. so for example if the input is ' happy days are here again! ' your function should return the list

def texted():

   text= input("Enter Text: ")

   text = text.lower()

nlist = ' '

   for char in text:

       if char.isalnum() == True:

           if char not in nlist:

               nlist = nlist + char

   nlist = sorted(nlist)

   print(nlist)

   return;

texted()

Explanation:

Step 1:

Define the function, i.e give it a name.

def texted():

Step 2:

Prompt the user to input a string i.e Text

text= input("Enter Text: ")

Step 3:

use the lower() string method. it is a method in python used to convert uppercase string characters to lower case.

text = text.lower()

Step 4:

Declare an empty string variable that will be used to store the characters while sorting.

nlist = ' '

Step 5:

for char in text:

       if char.isalnum() == True:

           if char not in nlist:

               nlist = nlist + char

-Use a for loop to iterate through all the characters in the text.

-.isalnum()  is a method in python that returns true if a character is an alphabet or a number.

The first if statement checks if it is an alphabet or a number and if it passes as true, it passes that alphabet or number to the next if statement.

- The second if statement checks if the character is not already in the list, if it is in the list it would not add it a second time.

If the character is not in the list, it adds the character to the list.

Step 6:

- sorts the list, i.e arranges the list in an alphabetical order.

- prints out the list, i.e produces an output of the list to your computer screen.

nlist = sorted(nlist)

print(nlist)

answer; (c) series 3; i believe this is the correct answer. good luck

answer

it would be true.