Create a class named testlease whose main() method declares four lease objects. call a getdata() method three times. within the method, prompt a user for values for each field for a lease, and return a lease object to the main() method where it is assigned to one of main()’s lease objects. do not prompt the user for values for the fourth lease object, but let it continue to hold the default values. then, in pass one of the lease objects to a showvalues() method that displays the data. then call the addpetfee() method using the passed lease object and confirm that the fee explanation statement is displayed. next, call the showvalues() method for the lease object again and confirm that the pet fee has been added to the rent. finally, call the showvalues() method with each of the other three objects; confirm that two hold the values you supplied as input and one holds the constructor default values. save the application as testlease. java.

Ac++an of of pi. in , pi is by : pi = 4 – 4/3 + 4/5 – 4/7 + 4/9 - 4/11 + 4/13 - 4/15 + 4/17 . ., to pi (9 ). , if 5 to pi,be as : pi = 4 - 4/3 + 4/5 - 4/7 + 4/9 = 4 – 1. + 0.8 - 0. + 0. = 3.. atoofbe to pi?

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }

In microsoft word, when you highlight existing text you want to replace, you're in              a.  advanced mode.    b.  automatic mode.    c.  basic mode.    d.  typeover mode