Write a function that receives an integer (n) argument and then computes the following based on the value of the integer: while the value of n is greater than 1, replace the integer with half of its value (n/2) if the integer is even. otherwise, replace the integer with three times its value, plus 1 (3*n + 1). make provision to count the number of values in (or the length of) the sequence that results. test your function: if n = 10, the sequence of integers is 5, 16, 8, 4, 2, 1 and so the length is 6. make a plot of the length of the sequence that occurs as a function of the integers from 2 to 30. for example, when n = 10, the length is 6 while for n = 15, the length is 17.

#include <iostream>

using namespace std;

int func(int n)//function..

{

   if(n>1)

   {

       if(n%2==0)//checking if the number is even.

       {

           return n/2;

       }

       else

       {

           return (3*n+1);

       }

   }

}

int main() {

   int num;//taking input of the n.

   cin>>num;

   while(num>1)//looping while the value of num is greater than 1.

   {

       int a=func(num);//calling function.

       cout<<a<<" ";//printing .

       num=a;//changing the value of num.

   }

return 0;

}

Input:-

10

Output:-

5 16 8 4 2 1

Explanation:

I have created the function named func. Then returning the values according to the problem.In the main function taking the input of integer num. Then calling a loop and calling the function till the value of n is greater than 1 and printing all the values returned by the function.

your answer is confidentiality

i've had the same problem. i generally just ignore it, as a ton of these "verified answers" are completely wrong.