Consider a system that has two cpus and each cpu has two threads (hyperthreading). suppose three processes, p0, pl, and p2, are started with run times of 5, 10 and 20 msec, respectively. how long will it take to complete the execution of these processes? discuss all possibilities depending on different processes scheduled to run on different cpus/threads, and what is the minimum execution time? assume that all three processes are 100% cpu bound, do not block during execution, and do not change cpus once assigned

Which of these is most responsible for differences between the twentieth century to the twenty-first century?

How to launch an app: steps to be successful? launching an app is a great idea, but it’s not that easy as we supposed to think. the majority of mobile applications don’t generate revenue because companies aren’t ready to be competitive. referring to our experience in successfully building and launching apps we hope to you omit these difficulties. we are going to talk about ideas, marketing, testing your product, its development, distribution and support. you will learn 8 product launch stages to succeed.

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }