Because the quicksort pivot’s key value is used to partition the array, following the partition the left subarray holds items smaller than the pivot, and the right subarray holds items larger. true or false?

Check my work the microprocessor is a(n) circuit, which is designed to process data based on a set of instructions. most desktop and laptop devices contain a microprocessor based on the standard. most tablets and smartphones contain processors based on technology. a microprocessor's circuitry is designed to perform a limited number of tasks contained in its set. during processing, an instruction is loaded into the processor's unit. data is loaded into registers in the processor's where arithmetic and logic operations are performed. microprocessor performance can be measured by its speed. other factors affecting overall processing performance include word size, cache size, and instruction set complexity. most digital devices contain only one microprocessor chip, but today's multi- processors contain circuitry that supports parallel processing. computers contain various kinds of memory. random memory is a special holding area for data, program instructions, and the system. it stores data on a temporary basis until the processor makes a data request. ram is different from disk storage because it is , which means that it can hold data only when the computer power is turned on. computers also contain read- memory, which is a type of non-volatile memory that provides a set of "hard-wired" instructions, called the loader, that a computer uses to boot up.

Look at the far left lane in the picture. explain what the red car is doing and what it needs to do to travel safely.

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }