)given the following algorithm (suppose n can only be even), answer the questions algorithm1(int n, const int s[]) { if (n==2) return; for (int i = 1; i < =n/2; i++) cout< < s[ i ] * s[ i+n/2 ]; } a) what is the output of the algorithm if n = 6, and s[1, 3, 6, 2, 2, 2] b) what is the best case complexity of the algorithm? c) what is the worst case complexity of the algorithm?

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the answer to your question would be something called hertz. the unit of measurement called a hertz, which is one cycle per second, is used to measure clock speed. within one cycle, your computer processes, refreshes, or updates itself to the changes that it is going through. in the case of computer clock speed, one hertz equals one tick per second. the clock speed of computers is usually measured in megahertz (mhz) or gigahertz (ghz)