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Given the following instructions beq rx, ry, offset; if (rx == ry) pc=pc+offset sub rx, ry, rz ; rx < - ry - rz addi rx, ry, imm ; rx < - ry + immediate value and rx, ry, rz ; rx < - ry and rz show how you can realize the effect of the following instruction: bgt rx, ry, offset; if (rx > ry) pc=pc+offset assume that the registers and the imm field are 8-bits wide. you can ignore the case that the sub instruction causes an overflow.

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Given the following instructions beq rx, ry, offset; if (rx == ry) pc=pc+offset sub rx, ry, rz ; r...
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