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Computers and Technology, 21.06.2019 22:20
This problem has been solved! see the answeran evil king has a cellar containing n bottles of expensive wine, and his guards have just caught a spy trying to poison the king’s wine. fortunately, the guards caught the spy after he succeeded in poisoning only one bottle. unfortunately, they don’t know which one. to make matters worse, the poison the spy used was very deadly; just one drop diluted even a billion to one will still kill someone. even so, the poison works slowly; it takes a full month for the person to die. design a scheme that allows the evil king to determine exactly which one of his wine bottles was poisoned in just one month’s time while expending at most o(logn) of his taste testers.you are not allowed to use n testers, one for each bottle, and see which one tester dies after 30 days.(no pseudocode needed. just answer in words, how many testers you use, how you use them and why you correctly identify the poisoned bottle in 30 days)
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Computers and Technology, 23.06.2019 00:30
Pl i need the answer now ! which one of the following is considered a peripheral? a software b mouse c usb connector d motherboard
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Computers and Technology, 23.06.2019 19:00
This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }
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Computers and Technology, 24.06.2019 13:30
To move an excel worksheet tab, simply right-click on it drag and drop it double-click on it delete it
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