You have a usb storage device that you cannot get working. you have enabled all appropriate usb options in the latest 2.2 kernel but still cannot get your device working. what is most likely the source of the problem?

This problem has been solved! see the answeran evil king has a cellar containing n bottles of expensive wine, and his guards have just caught a spy trying to poison the king’s wine. fortunately, the guards caught the spy after he succeeded in poisoning only one bottle. unfortunately, they don’t know which one. to make matters worse, the poison the spy used was very deadly; just one drop diluted even a billion to one will still kill someone. even so, the poison works slowly; it takes a full month for the person to die. design a scheme that allows the evil king to determine exactly which one of his wine bottles was poisoned in just one month’s time while expending at most o(logn) of his taste testers.you are not allowed to use n testers, one for each bottle, and see which one tester dies after 30 days.(no pseudocode needed. just answer in words, how many testers you use, how you use them and why you correctly identify the poisoned bottle in 30 days)

What allows you to create a wireless connection among your smart devices

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?