Milk of magnesia, a suspension of mg(oh)2 in water, reacts with stomach acid (hcl) in a neutralization reaction. mg(oh)2(s) + 2 hcl(aq) −→ 2 h2o(ℓ) + mgcl2(aq) what mass of mgcl2 will be produced if 1.82 g of mg(oh)2 reacts? answer in units of g.

Balanced equation for the above reaction is as follows;
Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O
stoichiometry of Mg(OH)₂ to MgCl₂ is 1:1
mass of Mg(OH)₂ reacted - 1.82 g
number of moles of Mg(OH)₂  - 1.82 g/ 58.3 g/mol = 0.0312 mol
number of Mg(OH)₂  moles reacted - number of MgCl₂ moles formed 
number of MgCl₂ moles formed - 0.0312 mol
mass of MgCl₂ formed - 0.0312 mol x 95.2 g/mol = 2.97 g
mass of MgCl₂ formed - 2.97 g