What is the mass occupied by 44.8 l of nitrogen (n2) at standard conditions?

Data Given:
                  Volume  =  V  =  44.8 L

                  Standard Pressure  =  P  =  1 atm

                  Standard Temperature  =  T  =  273 K

According to Ideal Gas Equation,

                            P V  =  n R T

Solving for n,

                            n  =  P V / R T

Putting values,

                            n  =  (1 atm × 44.8 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K)

                            n  =  1.99 mol

Now, calculating for mass,

                            n  =  Mass / M.mass
Or,
                            Mass  =  n × M.mass

                            Mass  =  1.99 mol × 28 g.mol⁻¹

                            Mass  =  55.72 grams

Ifound this on google “these two compounds have a different ionic structure. caesium ion is larger in size when compared to the sodium ion. the charge gets more area to spread out evenly. so caesium chloride has a lower melting point than sodium chloride.” i hope this you for what your looking for