Select the correct electron configuration for vanadium. (atomic number 23) 1s22s62p33s 23p44s23d5 1s22s22p63s 23p84s23d1 1s22s22p63s 23p64s23d3 1s22s22p53s 23p74s13d4

The  correct  electronic configuration of  vanadium  23  is

 1s^22s^22p^63s^23p^64s^23d^3

This  electronic configuration  is correct because it obeys  the Aufbau principle which  state  that  electrons  fill the atomic  orbital  of  the lowest  energy  before  occupying the higher level. S  orbital  can occupy a total of  2  electrons, p orbital  can  occupy a total of  6  electrons  while d orbital can occupy a total of  10 electrons. in the  electronic configuration above  an  s orbital  is filled  before p orbital  while  the  p  orbital is  filled before  the d orbital .

The correct answer is "atomic weight".