What volume of hydrogen gas is evolved from a reaction between 0.52 g of na and water? this gas is collected at 20 c and 745mmhg

The  volume of  hydrogen  gas  that evolved  is   calculated  as  follows
by  use  of   ideal  gas  equation

that  is  PV = nRT
P=745  mm hg
V= ?
R(gas  constant)= 62.36 L.mm hg/mol.k
T= 20 + 273 = 293 k
n=number  of  moles which is calculated as  follows
find the  moles  of Na  used
= 0.52/23=0.023  moles

write the reacting equation
2Na +2H2O =2NaOH +H2
by  use  of reacting  ratio  between  Na : H2  which  is  2:1  therefore  the mole  of H2 = 0.023/2 =0.0115  moles

by  making  the  volume  the   subject  of  the formula
v=nRT/P
V= (0.0115 x 62.36  x 293) / 745  = 0.283 L

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic