How many grams of phosphorus are in a sample of ca3(po4)2 that contains 50.0 grams of calcium

Answer : The mass of phosphorous present in sample is 25.8 grams.

Explanation :

First we have to calculate the moles of .

Molar mass of = 40 g/mole

Now we have to calculate the moles of phosphorous.

In the molecule , there are 3 moles of calcium, 2 moles of phosphorous and 8 moles of oxygen.

As, 3 mole of calcium contains 2 moles of phosphorous

So, 1.25 moles of calcium contains moles of phosphorous

Now we have to calculate the mass of phosphorous.

Molar mass of phosphorous = 31 g/mole

Therefore, the mass of phosphorous present in sample is 25.8 grams.