For the reaction cl2 + 2kbr → 2kcl + br2, how many moles of potassium chloride are produced from 331.1 g of potassium bromide?

Equation is as follow,

                                   Cl₂  +  2 KBr    →    2 KCl  +  Br₂

According to equation,

                 238 g (2 moles) KBr produced  =  2 Moles of KCl
So,
                      331.1 g of KBr will produce  =  X moles of KCl

Solving for X,
                                 X  =  (331.1 g × 2 mol) ÷ 238 g

                                 X  =  2.78 Moles of KCl
Result:
           331.1 g of KBr produces 2.78 Moles of KCl.

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