The molar solubility of ba3(po4)2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3(po4)2. the molar solubility of ba3(po4)2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3(po4)2. 5.55 x 10-41 5.33 x 10-37 8.16 x 10-31 6.00 x 10-39 4.94 x 10-49

Answer : The value of is

Explanation :

The solubility equilibrium reaction will be:

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

Given:

Molar solubility of = s =

Now put all the given values in the above expression, we get:

Therefore, the value of is