Calculate the mass of o2 needed to combine with 62g of phosphorus according to the balanced equation: 4p + 5o > 2p2o5

mass of oxygen = 80.077 grams

Explanation:
From the periodic table, we can find that:
atomic mass of oxygen = 16 grams
atomic mass of phosphorus = 30.97 grams

The balanced equation is:
4P + 5O₂ > 2P₂O₅

From this balanced equation we can note that:
4 moles of P are required to react with 5 moles of O₂
This means that:
4 * 30.97 = 123.88 grams
are required to react with
5 * (16*2) = 160 grams

Therefore, to know the mass of oxygen required to react with 62 grams of phosphorus, all we have to do is cross multiplication as follows:
123.88 grams of phosphorus > 160 grams of oxygen
62 grams of phosphorus > ?? grams of oxygen

mass of oxygen = (62*160) / (123.88) = 80.077 grams

Hope this helps :)

You would do 1500/4 and the answer is 375