What is the concentration of the unknown h3po4 solution? the neutralization reaction ish3po4(aq)+3naoh(aq)→3h2o(l)+na3po 4(aq) -g, com?

The concentration of the unknown H₃PO₄ solution : 0.0344 M

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

An acid-base titration there will be a change in the pH of the solution.

From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution

Acid-base titration formula

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

We complete the possible questions

A 34.00 mL sample of an unknown H₃PO₄ solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 26.98 mL of NaOH solution is added.

H₃PO₄ is a weak acid with valence 3 because it releases 3 H + atoms

H₃PO₄ -> 3H⁺ + PO₄⁻

NaOH is a strong base with valence 1 because it releases 1 OH- ions

NaOH ---> Na⁺ + OH-

We input the numbers into the formula:

M1.V1 n1= M2.V2 .n2

1 = H₃PO₄

2 = NaOH

M1.34 ml .3 = 0.130. 26.98 ml.1

M1 = 0.0344

So the molarity of the H₃PO₄ solution = 0.0344 M

the best tool to find the volume of that she needs to neutralize the acid

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Determine the endpoint of the titration.

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acid-base

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Identify the acids and the bases

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endpoint titration

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explanation: