It takes 46 ml of 0.124 m koh to neutralize 28.1 ml of h2so4 solution. what is the concentration of the h2so4 solution? answer in units of moles/liter.

The balanced equation of for the above reaction is as follows;
2KOH + H₂SO₄ ---> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
the number of KOH moles reacted - 0.124 mol/L x 0.046 L = 0.0057 mol
for complete neutralisation the base should react with acid in 2:1 molar ratio
if 2 mol of KOH reacts with 1 mol of H₂SO₄
then 0.0057 mol of KOH reacts with - 1/2 x 0.0057 mol = 0.0029 mol
the number of H₂SO₄ moles in 28.1 mL - 0.0029 mol
Molarity is number of H₂SO₄ moles in 1 L
therefore number of H₂SO₄ moles in 1 L - 0.0029 mol / 0.0281 L = 0.103 M
molarity of H₂SO₄ is 0.103 mol/L

If the water vapor content stays the same and the temperature drops, then the relative humidity increases. its vise versa.if the water vapor content stats the same and the temperature rises, the relative humidity decreases. so, yes, i'd say that temperature and humidity have a strong relationship.