Find the molar solubility of srco3 (ksp = 5.4 × 10−10) in pure water.

Answer is: molar solubility of strontium carbonate is 2.32·10⁻⁵ M.
Chemical reaction: SrCO₃(s) → Sr²⁺(aq) + CO₃²⁻(aq).

Ksp = 5.4·10⁻¹⁰.

s(SrCO₃) = ?M.
s(SrCO₃) = s(Sr²⁺) =s(CO₃²⁻) = x.

Ksp = s(Sr²⁺) · s(CO₃²⁻).
Ksp = x · x.

5.4·10⁻¹⁰ = x².

x = √5.4·10⁻¹⁰ = 2.32·10⁻⁵ M.

dynamic equilibrium is the answer.