Calculate the molar solubility and the solubility in g / l of agi at 25°c. the ksp of agi is 8.3 × 10−17.

Molar solubility is  and solubility in grams per liter is

Explanation: The equation for the reaction will be as follows:

1 mole of gives 1 mole of and 1 mole of .

Thus if solubility of is s moles/liter, solubility of   is s moles\liter and solubility of is s moles/liter.

Therefore,  

Solubility in grams/liter=

Solubility in grams/liter=

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.