Chemistry, 24.07.2019 21:30 trobbie817

For the reaction 2k(s)+br2(l)→2kbr(s) calculate how many grams of the product form when 21.4 g of br2 completely reacts. assume that there is more than enough of the other reactant.

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The balanced equation for the above reaction is as follows;
2K + Br₂ --> 2KBr
Stoichiometry of Br₂ to KBr is 1:2
we have been told that K is present which means that Br₂ is the limiting reactant. Limiting reactant is the reactant that is fully consumed in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of Br moles reacted - 21.4 g / 160 g/mol = 0.134 mol
According to stoichiometry,
1 mol of Br₂ forms 2 mol of KBr
therefore 0.134 mol of Br₂ forms 2x0.134 = 0.268 mol of KBr
mass of KBr formed - 0.268 mol x 119 g/mol = 31.9 g of KBr
a mass of 31.9 g of KBr is formed

Answer from: Quest

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: 1 - α α α = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

$k_{c}$ = $\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)v }$

or, $k_{c}$ = $\frac{\alpha ^{2} }{(1-\alpha) }$ (at v = 1l)

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: (1 - α)/0.5 α/0.5 α/0.5 = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

$\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)0.5 }$

$\frac{\alpha ^{2} }{(1-\alpha) }$ = $\frac{\alpha ^{2} }{(1-\alpha) 0.5}$

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

Answer from: Quest

8 carbon atoms forming single bonds with 18 hydrogen atoms; a triple bond exists between the third and fourth carbon atom from the right

explanation:

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For the reaction 2k(s)+br2(l)→2kbr(s) calculate how many grams of the product form when 21.4 g of br...

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