To neutralized 1.65g lioh, how much .150m hcl would be needed?

0.458 liters of HCl will be needed to neutralize LiOH.

Explanation: Reaction follows:

Stoichiometry ratio of LiOH and HCl is 1 : 1

which means, 1 mole of LiOH reacts with 1 mole of HCl.

Number of moles can be calculated by

mass of LiOH = 1.65g (Given)

molar mass of LiOH = 24g

Number of moles = 0.06875 moles

Number of moles of LiOH =  Number of moles of HCl

Moles of HCl = 0.06875 moles

and  

Molarity = 0.15 moles/Liter (Given)

Volume needed to neutralize LiOH will be,

Volume of HCl needed to neutralize LiOH = 0.458 litre.

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