Chemistry, 25.07.2019 05:00 dre8343

The chemical equation below shows the combustion of propane (c3h8). c3h8 + 5o2 mc012-1.jpg 3co2 + 4h2o the molar mass of oxygen gas (o2) is 32.00 g/mol. the molar mass of c3h8 is 44.1 g/mol. what mass of o2, in grams, is required to completely react with 0.025 g c3h8? 0.018 0.034 0.045 0.091

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Answer from: hmu323

The mass of O2 required to completely react with 0.025g C3H8 is calculated as follows

C3H8 + 5O2 = 3CO2 + 4H2o

calculate the moles of C3H8 that is moles=mass/molar mass
= 0.025g / 44.1 g/mol= 5.669 x10^-4 moles

by use of mole ratio from reacting equation between C3H8 to O2 which is 1:5 the moles of O2 = 5 x (5.669 x10^-4) = 2.83 x10^-3 moles

mass of O2 = moles x molar mass
= (2.83 x10^-3)moles x 32 g/mol = 0.091 g ( answer D)

Answer from: arianapowell56

0.091.

Explanation:

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

The answer is 1.82 j/g°c

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The chemical equation below shows the combustion of propane (c3h8). c3h8 + 5o2 mc012-1.jpg 3co2 + 4h...

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