The heat (or enthalpy) of fusion for ice is 0.334  kj/g. how many kilojoules of energy (q) are required to melt 22.4 g of ice at its melting point (0°c)?

According to this formula:

Q = ΔH fusion * mass (g)

when we have:

ΔH fusion (the heat (or enthalpy) of fusion = 0.334 kJ/g

and mass of ice = 22.4 g 

so by substitution, we can get the energy (Q) required to melt this mass of ice:

∴ Q = 0.334KJ/g * 22.4 g 

       = 7.48 KJ

∴ the energy required to melt 22.4 g of ice is = 7.48 KJ

The velocity would be 2 

Ibelieve the answer is b.2200 watts, because p=vi; p=220(10); then p=2200hope my answer has you : )