Determine if a bond between each pair of atoms would be pure covalent, polar covalent, or ionic. a. c and n b. n and s c. k and f d. n and n

Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,

                Less than 0.4 then it is Non Polar Covalent
                
                Between 0.4 and 1.7 then it is Polar Covalent 
            
                Greater than 1.7 then it is Ionic

For C and N,
                    E.N of Nitrogen      =   3.04
                    E.N of Carbon        =   2.55
                                                   
                    E.N Difference             0.49          (Weakly Polar Covalent)

For N and S,
                    E.N of Nitrogen      =   3.04
                    E.N of Sulfur          =   2.58
                                                   
                    E.N Difference             0.46           (Weakly Polar Covalent)

For K and F,
                    E.N of Fluorine       =   3.98
                    E.N of Potassium   =   0.28
                                                   
                    E.N Difference             3.70          (Ionic)

For N and N,
                    E.N of Nitrogen      =   3.04
                    E.N of Nitrogen      =   3.04
                                                   
                    E.N Difference             0              (Non Polar Covalent)

The nucleus inside an atom consists of positively-charged  protons  and neutrally-charged  neutrons. a  proton  is a subatomic particle with a positive electric charge. allprotons  are identical.