Calculate the solubility (in m) of cobalt(ii) hydroxide, co(oh)2(s) in h2o. ksp = 1.00×10-16 at a specific temperature.

according to this reaction:

by using the ICE table:

              CO(OH)2 → CO2+  +  2OH-

intial                                0             0

change                           +X           +2X

Equ                                   X              2X

when Ksp = [CO2][OH-]^2

by substitution:

3.6 x 10^-16 = X * (2X)^2

3.6 x 10^-16 = 4 X^3

∴X = 3.88 x 10^-6 M

The total number of electrons is 14

It is a product