Hbr addition to an alkene is a ch221 reaction with which you should be familiar. when peroxides are present, one regioisomer is observed while in the absence of peroxides, the other regioisomer is observed. two separate hbr addition reactions are carried out using the same starting alkene whose molecular formula is c5h10. one was carried out in the presence of peroxides and the other in the absence of peroxides. use the nmr spectra to decide which addition product was obtained from each reaction. nmr for product from first reaction whose molecular formula is c5h11br.

Your roll: experienced electron speech is adressed to: a new "freshman class" of electrons job: write a speech task: you are to pretend that you are giving a speech to a new group of electrons. be sure to mention their placement in an atom, their charge, and their role in chemical bonding (ionic and covalent) be specific!

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Answer asap need it by wednesday morning carry out the following calculations on ph and ka of from data. i. calculate the ph of 0.02m hcl ii. calculate the ph of 0.036m naoh iii. calculate the ph of 0.36m ca(oh)2 iv. calculate the ph of 0.16m ch3cooh which has ka = 1.74 x 10-5 mol dm-3 v. calculate ka for weak acid ha which has a ph of 3.65 at 0.30m concentration vi. calculate the ka of a solution made by mixing 15.0 cm3 0.2m ha and 60.0 cm3 0.31m a-. [ph= 3.80] vii. calculate the ph of a solution made by mixing 15.0 cm3 0.1m naoh and 35.0 cm3 0.2m hcooh. [ka = 1.82 x 10-4 m]