A1.00 l volume of hcl reacted completely with 2.00 l of 1.50 m ca(oh)2 according to the balanced chemical equation below. 2hcl + ca(oh)2 mc013-1.jpg cacl2 + 2h2o what was the molarity of the hcl solution? 0.375 m 1.50 m 3.00 m 6.00 m

The molarity  of the HCl  solution is   6.00M

Calculation

2HCl + Ca(OH)2→ CaCl2 +2H2O

 Step 1:find the   moles of Ca(OH)2

 =  molarity  x volume

=  2l x 1.5 mol/l =  3 .00 moles

Step 2:use the  mole ratio  of HCl : Ca(OH)2 to calculate the moles of HCl

That is Ca(OH)2 :HCl  is 2:1 therefore the moles of HCl= 3.00 moles x2= 6.00 moles.

step 3: find the molarity of HCl

molarity  of HCl = moles of HCL /  volume  in liters of HCl

   = 6.00 moles/ 1  L = 6.00 M

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