Calculate the rms speed of an oxygen gas molecule, o2, at 17.0 ∘c .

The μ rms speed = 475,433 m / s

Gas particles move randomly (both speed and direction, as vector)

Average velocities of gases can be expressed as root-mean-square velocity. (μ rms)

R = gas constant, 8,314 J / mol K

T = temperature, K

Mm = molar mass of the gas particles , Kg

μ rms = root mean square velocity of Gas Particles.,m/s

From this equation shows that the velocity of the gas is inversely proportional to the molar mass of the gas particles

μ ≅ 1 / Mm

So that the greater the molar mass of the gas particles, the smaller the speed (the slowest)

Oxygen gas molecule, O₂ has a molar mass: 0.032 kg / mol

T = 17 °C = 17 + 273 = 290 K

then:

kinetic molecular theory

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The gas particle that travels the slowest

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2b2t

explanation:

2b2t