Mercury can be obtained by reacting mercury(ii) sulfide with calcium oxide. how many grams of calcium oxide are needed to produce 36.0 g of hg? 4hgs(s) + 4cao(s) ® 4hg(l) + 3cas(s) + caso4

Answer is: 10,024 grams of calcium oxide are needed.
m(Hg) = 36 g.
n(Hg) = m(Hg) ÷ M(Hg).
n(Hg) = 36 g ÷ 200,6 g/mol.
n(Hg) = 0,179 mol.
From chemical reaction: n(Hg) : n(CaO) = 4 : 4 (1 : 1).
n(CaO) = 0,179 mol.
n(CaO) = 0,179 mol · 56 g/mol.
n(CaO) = 10,024 g.

Forgot the question hahaha

D-no effect on the rate