Given: h2o(aq) + h2o(l) h3o+(aq) + oh–(aq) δh°rxn > 0 when the temperature of a sample of pure water is raised above 25°c,

When Δ H > 0 that means this is an endothermic reaction, and we can assume heat as one of the reactants. SO when the temperature increases so the reaction will move rightward to decrease the reactants and increase the products and as the products increase it will make the Kw increase also as
 Kw = [Products] /[reactants].

So our answer will be: the value of Kw will increase.

Hbr dissociates to form h+ and br-ca(oh)2 dissociates to form ca2+ and 2oh-the h+ and oh- react to form waterassuming the reactants are dissolved in water, the net reaction is h+ + oh- —> h2oif you’re asked to show all components of the reaction, the complete reaction is 2hbr + ca(oh)2 —> cabr2 + 2h2o