Calculate [h+] and [oh−] for a neutral solution at this temperature. express your answers using two significant figures. enter your answers separated by a comma.

When we have Kw = 1.2x10^-15
and according to Kw formula:
Kw = [OH-] [H+]
by substitution:

1.2x10^-15 = [OH-][H+]
when the solution is neutral that means:
[OH-] = [H+]
∴1.2X10^-15 = X^2
∴X = 3.46 x 10^-8
∴[OH-] = [H+] = 3.46x10^-8

Outermost (valence) electrons