In the reaction represented by the equation 2al2o3 ® 4al + 3o2, what is the mole ratio of the products aluminum and oxygen?

4 : 3

Explanation:
The balanced chemical equation is given as follows:
2Al₂O₃ > 4Al + 3O₂
Now, from this equation we can note that:
For every 4 moles of aluminum moles produced, corresponding 3 oxygen moles are produced.
This means that the ratio between the formation of aluminum to the formation of oxygen moles is 4:3

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