Apiece of copper at 10 °c is dropped into a glass of water at 35 °c. which statement is correct? a. heat will flow from the copper to the water in the glass until both reach the same temperature. b. heat will flow from the water in the glass to the copper until both reach the same temperature. c. the final temperature of the water in the glass and the copper will be 10 °c. d. the final temperature of the water in the glass and the copper will be 35 °c.

The correct answer is option B, that is, heat will flow from the water in the glass to the copper until both reach the same temperature.

Explanation:

Let us see a perfectly thermal insulation system with a glass of water at higher temperatures and a piece of copper at a lower temperature, and when both encounters each other than water will lose some of the heat and that heat will be gained by the copper. The procedure will take place until and unless both attain a similar temperature. After attaining a similar temperature, there will be no change in temperature or heat between the two.  The change in heat is a function of temperature difference.

a. a clone will be physically identical to the original, but won’t be genetically identical

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answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.