2. in the reaction no + no2 ⇌ n2o3, an experiment finds equilibrium concentrations of [no] = 3.8 m, [no2] = 3.9 m, and [n2o3] = 1.3 m. what is the equilibrium constant kc for this reaction? a. 0.064 b. 0.088 c. 0.114 d. 0.193

Kc= concentration  of  product  divided  by  concentration   of  reactant
NO +  NO2  >  N2O3

Kc =(N2O3)  /  (No)(NO2)

Kc= ( 1.3  )/{ (3.9)(3.8) }

Kc=0.088 (  answer  B)

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