What happens when naoh is added to a buffer composed of ch3cooh and ch3coo−?

Hello!

When NaOH is added to a buffer composed of CH₃COOH and CH₃COO⁻, the following reactions happen:

-First, the NaOH is neutralized by CH₃COOH:

NaOH + CH₃COOH → H₂O + CH₃COONa

-Second, the CH₃COONa dissociates in its ions:

CH₃COONa  → CH₃COO⁻ + Na⁺

-Finally, CH₃COO⁻ (a weak base) reacts with water to form OH⁻ ions and regenerate CH₃COOH

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

By this sequence of reactions, the buffer can mitigate the effect of the strong base added.

Have a nice day!

The correct answer is b