Draw the lewis structure with the atoms arranged as hclo. include all non-bonding electronsand non-zero formal charges. do not draw cl with an expanded octet.

An image is attached depicting the Lewis structure of HClO with the atoms arranged in that order. The result is a single bond between each atom. We can calculate the formal charge of each atom with the following formula:

Formal charge = (Valence electrons) - (electrons shared in bonds) - (non-bonded electrons)

H: Formal charge = 1 - 1 - 0 = 0

Cl: Formal charge = 7 - 2 - 4 = +1

O: Formal charge = 6 - 1 - 6 = -1

This structure is not the actual way these atoms arrange. The atoms will actually arrange in the order of H-O-Cl to form hypochlorous acid with a single bond between the three atoms and formal charges of 0 on each atom.

The answer is b because a,c,and d are opinons