Calculate the molarity of a solution made by adding 45.4 g of nano3 to a flask and dissolving it with water to create a total volume of 2.50 l.

molarity is defined as the number of moles of solute in 1 L of solution.
molar mass of NaNO₃ = 85 g/mol
             
number of moles of NaNO₃ = 45.4 g / 85 g/mol = 0.534 mol
 
there are 0.534 mol in 2.50 L solution
                         
therefore number of NaNO₃ moles in 1 L solution = 0.534 mol / 2.50 L = 0.214 M
molarity of solution is 0.214 M