This solution contains equal concentrations of both hf(aq) and naf(aq). write the proton transfer equilibrium (net ionic) reaction that includes f– as a reactant. include states of matter.

We are asked to provide the net ionic equation for the reaction of HF (aq) and NaF (aq). HF is a weak acid and is in the following equilibrium:

HF (aq) ⇄ H⁺ (aq) + F⁻ (aq)

Meanwhile, NaF (aq) is an ionic compound that will dissociate completely in aqueous solutions:

NaF (aq) → Na⁺ (aq) + F⁻ (aq)

We can combine the ionic species with HF, as we are told to show F⁻ as a reactant:

HF (aq) + Na⁺ (aq) + F⁻ (aq) → HF (aq) + Na⁺ (aq) + F⁻ (aq)

We can eliminate the spectator ions, which in this case are Na⁺ ions, and this leaves us with the net ionic equation involving F⁻:

HF (aq) + F⁻ (aq) → HF (aq) + F⁻ (aq)

In this instance, the proton is just transferred between F⁻ ions and the end result is the formation of more HF, so there is no net reaction taking place.

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