When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of ca(oh)2? ca(oh)2 + h3po3 yields h2o + ca3(po3)2

Ans: Lowest coefficient in front of Ca(OH)2 is 3

Given equation:

Ca(OH)2 + H3PO3 → Ca3(PO3)2 + H2O

Reactants:                  Products:

Ca = 1                          Ca = 3

O = 5                           O = 7  

H = 5                           H = 2

P = 1                             P = 2

Balanced equation:

3Ca(OH)2 + 2H3PO3 → Ca3(PO3)2 + 6H2O

ill try to . no promises tho.

explanation:

i believe it is c.) 1575 j.