What is the mass in grams of 0.433 mol of ca(no3)2

The molar mass of the components making up Ca(NO₃)₂ are as follows;
Ca - 40 g/mol
N - 14 g/mol
O - 16 g/mol
the molar mass of the compound is calculated as follows;
Ca(NO₃)₂ --> 40 + 2(14 + 16x3)
               = 164 g/mol
1 mol of the compound weighs 164 g
Therefore 0.433 mol = 164 g/mol x 0.433 mol
                                 = 71.0g
the mass of 0.433 mol of the compound is 71.0 g

It idk haha what are we doing?