24.0 ml of a 0.120 m ca(oh)2 solution is required to titrate 160 ml of an hcl solution to its equivalence point. find the moles of hcl and its concentration in molarity.

The balanced reaction is as follows;
Ca(OH)₂ + 2HCl ---> CaCl₂ + 2H₂O
  stoichiometry of Ca(OH)₂ to HCl is 1:2
number of moles of Ca(OH)₂ reacted = 0.120 mol/L x 0.0240 L = 0.00288 mol according to molar ratio of 1:2 number of HCl moles reacted = twice the number of Ca(OH)₂ moles reacted
number of HCl moles reacted = 0.00288 mol x 2 = 0.00576 mol
number of HCl moles in 160 mL - 0.00576 mol
therefore number of HCl moles in 1000 mL - 0.00576 mol / 160 mL x 1000 mL = 0.036 mol
molarity of HCl = 0.036 M

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