Answers: 1
![pH=-log[H^+]](/tpl/images/0150/1647/15713.png)
![9.88=-log[H^+]](/tpl/images/0150/1647/6cd66.png)
![[H^+]=antilog(-9.88)](/tpl/images/0150/1647/c4edc.png)
![[H^+]=1.32\times 10^{-10}M](/tpl/images/0150/1647/d0896.png)
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Calculate the [h+] in a solution that has a ph of 9.88....
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