Fe2o3(s)+3co(g)⟶2fe(s)+3co2(g) how many moles of fe2o3 are necessary to produce 1.648 mol of co2?

Hey there!:

Fe2O3(s) + 3 CO(g) = 2 Fe(s) + 3 CO2(g) 
      ↓                                              ↓
 
1 mole Fe2O3 3 moles CO2
moles Fe2O3 ? 1.648 moles CO2

moles Fe2O3  = 1.648 * 1 / 3

moles Fe2O3 = 1.648 / 3

=>  0.5493 moles of Fe2O3

hope this helps!

Dmight be the correct answer